﻿<?xml version="1.0" encoding="utf-8" standalone="yes"?><rss version="2.0" xmlns:dc="http://purl.org/dc/elements/1.1/" xmlns:trackback="http://madskills.com/public/xml/rss/module/trackback/" xmlns:wfw="http://wellformedweb.org/CommentAPI/" xmlns:slash="http://purl.org/rss/1.0/modules/slash/"><channel><title>IT博客-Java部落-随笔分类-数据结构与算法</title><link>http://www.cnitblog.com/intrl/category/8222.html</link><description>大家齐努力，成功共分享！
          ------庖丁解牛</description><language>zh-cn</language><lastBuildDate>Mon, 26 Sep 2011 11:28:24 GMT</lastBuildDate><pubDate>Mon, 26 Sep 2011 11:28:24 GMT</pubDate><ttl>60</ttl><item><title>【算法】int[]数组按地址排序</title><link>http://www.cnitblog.com/intrl/archive/2009/06/01/58956.html</link><dc:creator>intrl</dc:creator><author>intrl</author><pubDate>Mon, 01 Jun 2009 15:47:00 GMT</pubDate><guid>http://www.cnitblog.com/intrl/archive/2009/06/01/58956.html</guid><wfw:comment>http://www.cnitblog.com/intrl/comments/58956.html</wfw:comment><comments>http://www.cnitblog.com/intrl/archive/2009/06/01/58956.html#Feedback</comments><slash:comments>2</slash:comments><wfw:commentRss>http://www.cnitblog.com/intrl/comments/commentRss/58956.html</wfw:commentRss><trackback:ping>http://www.cnitblog.com/intrl/services/trackbacks/58956.html</trackback:ping><description><![CDATA[&nbsp;&nbsp;&nbsp;&nbsp; 摘要: int[]数组按地址排序&nbsp;&nbsp;<a href='http://www.cnitblog.com/intrl/archive/2009/06/01/58956.html'>阅读全文</a><img src ="http://www.cnitblog.com/intrl/aggbug/58956.html" width = "1" height = "1" /><br><br><div align=right><a style="text-decoration:none;" href="http://www.cnitblog.com/intrl/" target="_blank">intrl</a> 2009-06-01 23:47 <a href="http://www.cnitblog.com/intrl/archive/2009/06/01/58956.html#Feedback" target="_blank" style="text-decoration:none;">发表评论</a></div>]]></description></item><item><title>【算法】邮票问题</title><link>http://www.cnitblog.com/intrl/archive/2009/05/22/58713.html</link><dc:creator>intrl</dc:creator><author>intrl</author><pubDate>Fri, 22 May 2009 15:52:00 GMT</pubDate><guid>http://www.cnitblog.com/intrl/archive/2009/05/22/58713.html</guid><wfw:comment>http://www.cnitblog.com/intrl/comments/58713.html</wfw:comment><comments>http://www.cnitblog.com/intrl/archive/2009/05/22/58713.html#Feedback</comments><slash:comments>2</slash:comments><wfw:commentRss>http://www.cnitblog.com/intrl/comments/commentRss/58713.html</wfw:commentRss><trackback:ping>http://www.cnitblog.com/intrl/services/trackbacks/58713.html</trackback:ping><description><![CDATA[&nbsp;&nbsp;&nbsp;&nbsp; 摘要: 1.      问题描述<br>设有n种不同面值a1, a2,…, an的邮票，规定每封信最多贴m张邮票。对于给定的m，n，求出最大的邮资连续区间。例如，给定n=3，m=3，邮票面值分别为2, 3, 5，则最大的邮资连续区间为[2，13]。&nbsp;&nbsp;<a href='http://www.cnitblog.com/intrl/archive/2009/05/22/58713.html'>阅读全文</a><img src ="http://www.cnitblog.com/intrl/aggbug/58713.html" width = "1" height = "1" /><br><br><div align=right><a style="text-decoration:none;" href="http://www.cnitblog.com/intrl/" target="_blank">intrl</a> 2009-05-22 23:52 <a href="http://www.cnitblog.com/intrl/archive/2009/05/22/58713.html#Feedback" target="_blank" style="text-decoration:none;">发表评论</a></div>]]></description></item><item><title>【算法】黑白点的匹配</title><link>http://www.cnitblog.com/intrl/archive/2009/04/26/56734.html</link><dc:creator>intrl</dc:creator><author>intrl</author><pubDate>Sun, 26 Apr 2009 05:00:00 GMT</pubDate><guid>http://www.cnitblog.com/intrl/archive/2009/04/26/56734.html</guid><wfw:comment>http://www.cnitblog.com/intrl/comments/56734.html</wfw:comment><comments>http://www.cnitblog.com/intrl/archive/2009/04/26/56734.html#Feedback</comments><slash:comments>0</slash:comments><wfw:commentRss>http://www.cnitblog.com/intrl/comments/commentRss/56734.html</wfw:commentRss><trackback:ping>http://www.cnitblog.com/intrl/services/trackbacks/56734.html</trackback:ping><description><![CDATA[&nbsp;&nbsp;&nbsp;&nbsp; 摘要: 1、问题描述<br>设平面上分布着n个白点和n个黑点，每个点用一对坐标（x, y）表示。一个黑点b=（xb,yb）支配一个白点w=(xw, yw)当且仅当xb>=xw和yb>=yw。若黑点b支配白点w，则黑点b和白点w可匹配（可形成一个匹配对）。在一个黑点最多只能与一个白点匹配，一个白点最多只能与一个黑点匹配的前提下，求n个白点和n个黑点的最大匹配对数。&nbsp;&nbsp;<a href='http://www.cnitblog.com/intrl/archive/2009/04/26/56734.html'>阅读全文</a><img src ="http://www.cnitblog.com/intrl/aggbug/56734.html" width = "1" height = "1" /><br><br><div align=right><a style="text-decoration:none;" href="http://www.cnitblog.com/intrl/" target="_blank">intrl</a> 2009-04-26 13:00 <a href="http://www.cnitblog.com/intrl/archive/2009/04/26/56734.html#Feedback" target="_blank" style="text-decoration:none;">发表评论</a></div>]]></description></item><item><title>【算法】递归算法举例</title><link>http://www.cnitblog.com/intrl/archive/2009/04/25/56718.html</link><dc:creator>intrl</dc:creator><author>intrl</author><pubDate>Sat, 25 Apr 2009 15:43:00 GMT</pubDate><guid>http://www.cnitblog.com/intrl/archive/2009/04/25/56718.html</guid><wfw:comment>http://www.cnitblog.com/intrl/comments/56718.html</wfw:comment><comments>http://www.cnitblog.com/intrl/archive/2009/04/25/56718.html#Feedback</comments><slash:comments>2</slash:comments><wfw:commentRss>http://www.cnitblog.com/intrl/comments/commentRss/56718.html</wfw:commentRss><trackback:ping>http://www.cnitblog.com/intrl/services/trackbacks/56718.html</trackback:ping><description><![CDATA[&nbsp;&nbsp;&nbsp;&nbsp; 摘要: 递归算法举例（Java实现）&nbsp;&nbsp;<a href='http://www.cnitblog.com/intrl/archive/2009/04/25/56718.html'>阅读全文</a><img src ="http://www.cnitblog.com/intrl/aggbug/56718.html" width = "1" height = "1" /><br><br><div align=right><a style="text-decoration:none;" href="http://www.cnitblog.com/intrl/" target="_blank">intrl</a> 2009-04-25 23:43 <a href="http://www.cnitblog.com/intrl/archive/2009/04/25/56718.html#Feedback" target="_blank" style="text-decoration:none;">发表评论</a></div>]]></description></item><item><title>【算法】归并排序</title><link>http://www.cnitblog.com/intrl/archive/2009/04/25/56717.html</link><dc:creator>intrl</dc:creator><author>intrl</author><pubDate>Sat, 25 Apr 2009 15:41:00 GMT</pubDate><guid>http://www.cnitblog.com/intrl/archive/2009/04/25/56717.html</guid><wfw:comment>http://www.cnitblog.com/intrl/comments/56717.html</wfw:comment><comments>http://www.cnitblog.com/intrl/archive/2009/04/25/56717.html#Feedback</comments><slash:comments>0</slash:comments><wfw:commentRss>http://www.cnitblog.com/intrl/comments/commentRss/56717.html</wfw:commentRss><trackback:ping>http://www.cnitblog.com/intrl/services/trackbacks/56717.html</trackback:ping><description><![CDATA[&nbsp;&nbsp;&nbsp;&nbsp; 摘要: 归并排序Java实现&nbsp;&nbsp;<a href='http://www.cnitblog.com/intrl/archive/2009/04/25/56717.html'>阅读全文</a><img src ="http://www.cnitblog.com/intrl/aggbug/56717.html" width = "1" height = "1" /><br><br><div align=right><a style="text-decoration:none;" href="http://www.cnitblog.com/intrl/" target="_blank">intrl</a> 2009-04-25 23:41 <a href="http://www.cnitblog.com/intrl/archive/2009/04/25/56717.html#Feedback" target="_blank" style="text-decoration:none;">发表评论</a></div>]]></description></item><item><title>【算法】快速排序</title><link>http://www.cnitblog.com/intrl/archive/2009/04/25/56716.html</link><dc:creator>intrl</dc:creator><author>intrl</author><pubDate>Sat, 25 Apr 2009 15:38:00 GMT</pubDate><guid>http://www.cnitblog.com/intrl/archive/2009/04/25/56716.html</guid><wfw:comment>http://www.cnitblog.com/intrl/comments/56716.html</wfw:comment><comments>http://www.cnitblog.com/intrl/archive/2009/04/25/56716.html#Feedback</comments><slash:comments>0</slash:comments><wfw:commentRss>http://www.cnitblog.com/intrl/comments/commentRss/56716.html</wfw:commentRss><trackback:ping>http://www.cnitblog.com/intrl/services/trackbacks/56716.html</trackback:ping><description><![CDATA[&nbsp;&nbsp;&nbsp;&nbsp; 摘要: 快速排序Java实现&nbsp;&nbsp;<a href='http://www.cnitblog.com/intrl/archive/2009/04/25/56716.html'>阅读全文</a><img src ="http://www.cnitblog.com/intrl/aggbug/56716.html" width = "1" height = "1" /><br><br><div align=right><a style="text-decoration:none;" href="http://www.cnitblog.com/intrl/" target="_blank">intrl</a> 2009-04-25 23:38 <a href="http://www.cnitblog.com/intrl/archive/2009/04/25/56716.html#Feedback" target="_blank" style="text-decoration:none;">发表评论</a></div>]]></description></item><item><title>【算法】插入排序</title><link>http://www.cnitblog.com/intrl/archive/2009/04/25/56715.html</link><dc:creator>intrl</dc:creator><author>intrl</author><pubDate>Sat, 25 Apr 2009 15:37:00 GMT</pubDate><guid>http://www.cnitblog.com/intrl/archive/2009/04/25/56715.html</guid><wfw:comment>http://www.cnitblog.com/intrl/comments/56715.html</wfw:comment><comments>http://www.cnitblog.com/intrl/archive/2009/04/25/56715.html#Feedback</comments><slash:comments>0</slash:comments><wfw:commentRss>http://www.cnitblog.com/intrl/comments/commentRss/56715.html</wfw:commentRss><trackback:ping>http://www.cnitblog.com/intrl/services/trackbacks/56715.html</trackback:ping><description><![CDATA[&nbsp;&nbsp;&nbsp;&nbsp; 摘要: 插入排序Java实现&nbsp;&nbsp;<a href='http://www.cnitblog.com/intrl/archive/2009/04/25/56715.html'>阅读全文</a><img src ="http://www.cnitblog.com/intrl/aggbug/56715.html" width = "1" height = "1" /><br><br><div align=right><a style="text-decoration:none;" href="http://www.cnitblog.com/intrl/" target="_blank">intrl</a> 2009-04-25 23:37 <a href="http://www.cnitblog.com/intrl/archive/2009/04/25/56715.html#Feedback" target="_blank" style="text-decoration:none;">发表评论</a></div>]]></description></item><item><title>【算法】选择排序</title><link>http://www.cnitblog.com/intrl/archive/2009/04/25/56714.html</link><dc:creator>intrl</dc:creator><author>intrl</author><pubDate>Sat, 25 Apr 2009 15:34:00 GMT</pubDate><guid>http://www.cnitblog.com/intrl/archive/2009/04/25/56714.html</guid><wfw:comment>http://www.cnitblog.com/intrl/comments/56714.html</wfw:comment><comments>http://www.cnitblog.com/intrl/archive/2009/04/25/56714.html#Feedback</comments><slash:comments>0</slash:comments><wfw:commentRss>http://www.cnitblog.com/intrl/comments/commentRss/56714.html</wfw:commentRss><trackback:ping>http://www.cnitblog.com/intrl/services/trackbacks/56714.html</trackback:ping><description><![CDATA[&nbsp;&nbsp;&nbsp;&nbsp; 摘要: 选择排序Java实现<br>&nbsp;&nbsp;<a href='http://www.cnitblog.com/intrl/archive/2009/04/25/56714.html'>阅读全文</a><img src ="http://www.cnitblog.com/intrl/aggbug/56714.html" width = "1" height = "1" /><br><br><div align=right><a style="text-decoration:none;" href="http://www.cnitblog.com/intrl/" target="_blank">intrl</a> 2009-04-25 23:34 <a href="http://www.cnitblog.com/intrl/archive/2009/04/25/56714.html#Feedback" target="_blank" style="text-decoration:none;">发表评论</a></div>]]></description></item><item><title>【算法】冒泡排序</title><link>http://www.cnitblog.com/intrl/archive/2009/04/25/56713.html</link><dc:creator>intrl</dc:creator><author>intrl</author><pubDate>Sat, 25 Apr 2009 15:33:00 GMT</pubDate><guid>http://www.cnitblog.com/intrl/archive/2009/04/25/56713.html</guid><wfw:comment>http://www.cnitblog.com/intrl/comments/56713.html</wfw:comment><comments>http://www.cnitblog.com/intrl/archive/2009/04/25/56713.html#Feedback</comments><slash:comments>0</slash:comments><wfw:commentRss>http://www.cnitblog.com/intrl/comments/commentRss/56713.html</wfw:commentRss><trackback:ping>http://www.cnitblog.com/intrl/services/trackbacks/56713.html</trackback:ping><description><![CDATA[&nbsp;&nbsp;&nbsp;&nbsp; 摘要: 冒泡排序Java实现&nbsp;&nbsp;<a href='http://www.cnitblog.com/intrl/archive/2009/04/25/56713.html'>阅读全文</a><img src ="http://www.cnitblog.com/intrl/aggbug/56713.html" width = "1" height = "1" /><br><br><div align=right><a style="text-decoration:none;" href="http://www.cnitblog.com/intrl/" target="_blank">intrl</a> 2009-04-25 23:33 <a href="http://www.cnitblog.com/intrl/archive/2009/04/25/56713.html#Feedback" target="_blank" style="text-decoration:none;">发表评论</a></div>]]></description></item><item><title>【算法】加油问题</title><link>http://www.cnitblog.com/intrl/archive/2009/04/19/56471.html</link><dc:creator>intrl</dc:creator><author>intrl</author><pubDate>Sat, 18 Apr 2009 17:10:00 GMT</pubDate><guid>http://www.cnitblog.com/intrl/archive/2009/04/19/56471.html</guid><wfw:comment>http://www.cnitblog.com/intrl/comments/56471.html</wfw:comment><comments>http://www.cnitblog.com/intrl/archive/2009/04/19/56471.html#Feedback</comments><slash:comments>0</slash:comments><wfw:commentRss>http://www.cnitblog.com/intrl/comments/commentRss/56471.html</wfw:commentRss><trackback:ping>http://www.cnitblog.com/intrl/services/trackbacks/56471.html</trackback:ping><description><![CDATA[&nbsp;&nbsp;&nbsp;&nbsp; 摘要: 1. 问题描述 <br>一个旅行家想驾驶汽车从城市A到城市B（设出发时油箱是空的）。给定两个城市之间的距离dis、汽车油箱的容量c、每升汽油能行驶的距离d、沿途油站数n、油站i离出发点的距离d[i]以及该站每升汽油的价格p[i],i=1,2,…,n。设d[1]=0<d[2]<…<d[n]。要花最少的油费从城市A到城市B，在每个加油站应加多少油，最少花费为多少？<br>2.……&nbsp;&nbsp;<a href='http://www.cnitblog.com/intrl/archive/2009/04/19/56471.html'>阅读全文</a><img src ="http://www.cnitblog.com/intrl/aggbug/56471.html" width = "1" height = "1" /><br><br><div align=right><a style="text-decoration:none;" href="http://www.cnitblog.com/intrl/" target="_blank">intrl</a> 2009-04-19 01:10 <a href="http://www.cnitblog.com/intrl/archive/2009/04/19/56471.html#Feedback" target="_blank" style="text-decoration:none;">发表评论</a></div>]]></description></item><item><title>【算法】求数列中的第1～k小元素</title><link>http://www.cnitblog.com/intrl/archive/2009/04/11/56266.html</link><dc:creator>intrl</dc:creator><author>intrl</author><pubDate>Sat, 11 Apr 2009 12:07:00 GMT</pubDate><guid>http://www.cnitblog.com/intrl/archive/2009/04/11/56266.html</guid><wfw:comment>http://www.cnitblog.com/intrl/comments/56266.html</wfw:comment><comments>http://www.cnitblog.com/intrl/archive/2009/04/11/56266.html#Feedback</comments><slash:comments>0</slash:comments><wfw:commentRss>http://www.cnitblog.com/intrl/comments/commentRss/56266.html</wfw:commentRss><trackback:ping>http://www.cnitblog.com/intrl/services/trackbacks/56266.html</trackback:ping><description><![CDATA[&nbsp;&nbsp;&nbsp;&nbsp; 摘要: 1.问题描述<br>设计算法实现在一个具有在n各互不相同元素的数组A[1…n]中找出所有前k个最小元素的问题，这里k不是常量，即它是输入数据的一部分。要求算法的时间复杂性为Θ(n)。&nbsp;&nbsp;<a href='http://www.cnitblog.com/intrl/archive/2009/04/11/56266.html'>阅读全文</a><img src ="http://www.cnitblog.com/intrl/aggbug/56266.html" width = "1" height = "1" /><br><br><div align=right><a style="text-decoration:none;" href="http://www.cnitblog.com/intrl/" target="_blank">intrl</a> 2009-04-11 20:07 <a href="http://www.cnitblog.com/intrl/archive/2009/04/11/56266.html#Feedback" target="_blank" style="text-decoration:none;">发表评论</a></div>]]></description></item><item><title>【算法】L型组件填图问题</title><link>http://www.cnitblog.com/intrl/archive/2009/04/11/56263.html</link><dc:creator>intrl</dc:creator><author>intrl</author><pubDate>Sat, 11 Apr 2009 11:10:00 GMT</pubDate><guid>http://www.cnitblog.com/intrl/archive/2009/04/11/56263.html</guid><wfw:comment>http://www.cnitblog.com/intrl/comments/56263.html</wfw:comment><comments>http://www.cnitblog.com/intrl/archive/2009/04/11/56263.html#Feedback</comments><slash:comments>0</slash:comments><wfw:commentRss>http://www.cnitblog.com/intrl/comments/commentRss/56263.html</wfw:commentRss><trackback:ping>http://www.cnitblog.com/intrl/services/trackbacks/56263.html</trackback:ping><description><![CDATA[&nbsp;&nbsp;&nbsp;&nbsp; 摘要:  1.问题描述<br>设B是一个n×n棋盘，n=2k,(k=1,2,3,…)。用分治法设计一个算法，使得：用若干个L型条块可以覆盖住B的除一个特殊方格外的所有方格。其中，一个L型条块可以覆盖3个方格。且任意两个L型条块不能重叠覆盖棋盘。<br>    例如：如果n=2，则存在4个方格，其中，除一个方格外，其余3个方格可被一L型条块覆盖；当n=4时，则存在16个方格，其中，除一个方格外，其余15个方格被5个L型条块覆盖。&nbsp;&nbsp;<a href='http://www.cnitblog.com/intrl/archive/2009/04/11/56263.html'>阅读全文</a><img src ="http://www.cnitblog.com/intrl/aggbug/56263.html" width = "1" height = "1" /><br><br><div align=right><a style="text-decoration:none;" href="http://www.cnitblog.com/intrl/" target="_blank">intrl</a> 2009-04-11 19:10 <a href="http://www.cnitblog.com/intrl/archive/2009/04/11/56263.html#Feedback" target="_blank" style="text-decoration:none;">发表评论</a></div>]]></description></item><item><title>【算法】格雷码问题</title><link>http://www.cnitblog.com/intrl/archive/2009/04/11/56262.html</link><dc:creator>intrl</dc:creator><author>intrl</author><pubDate>Sat, 11 Apr 2009 10:46:00 GMT</pubDate><guid>http://www.cnitblog.com/intrl/archive/2009/04/11/56262.html</guid><wfw:comment>http://www.cnitblog.com/intrl/comments/56262.html</wfw:comment><comments>http://www.cnitblog.com/intrl/archive/2009/04/11/56262.html#Feedback</comments><slash:comments>0</slash:comments><wfw:commentRss>http://www.cnitblog.com/intrl/comments/commentRss/56262.html</wfw:commentRss><trackback:ping>http://www.cnitblog.com/intrl/services/trackbacks/56262.html</trackback:ping><description><![CDATA[&nbsp;&nbsp;&nbsp;&nbsp; 摘要: 1.问题描述 <br>对于给定的正整数n，格雷码为满足如下条件的一个编码序列：<br>(1) 序列由2n个编码组成，每个编码都是长度为n的二进制位串。<br>(2) 序列中无相同的编码。<br>(3) 序列中位置相邻的两个编码恰有一位不同。<br>例如：n=2时的格雷码为：{00, 01, 11, 10}。<br>设计求格雷码的递归算法并实现。&nbsp;&nbsp;<a href='http://www.cnitblog.com/intrl/archive/2009/04/11/56262.html'>阅读全文</a><img src ="http://www.cnitblog.com/intrl/aggbug/56262.html" width = "1" height = "1" /><br><br><div align=right><a style="text-decoration:none;" href="http://www.cnitblog.com/intrl/" target="_blank">intrl</a> 2009-04-11 18:46 <a href="http://www.cnitblog.com/intrl/archive/2009/04/11/56262.html#Feedback" target="_blank" style="text-decoration:none;">发表评论</a></div>]]></description></item><item><title>【算法】整数集合分解</title><link>http://www.cnitblog.com/intrl/archive/2009/04/11/56261.html</link><dc:creator>intrl</dc:creator><author>intrl</author><pubDate>Sat, 11 Apr 2009 10:42:00 GMT</pubDate><guid>http://www.cnitblog.com/intrl/archive/2009/04/11/56261.html</guid><wfw:comment>http://www.cnitblog.com/intrl/comments/56261.html</wfw:comment><comments>http://www.cnitblog.com/intrl/archive/2009/04/11/56261.html#Feedback</comments><slash:comments>0</slash:comments><wfw:commentRss>http://www.cnitblog.com/intrl/comments/commentRss/56261.html</wfw:commentRss><trackback:ping>http://www.cnitblog.com/intrl/services/trackbacks/56261.html</trackback:ping><description><![CDATA[&nbsp;&nbsp;&nbsp;&nbsp; 摘要: 1.问题描述 <br>令S为一个n个正整数的集合，n为偶数。请设计一个有效算法将S分成两个子集S1和S2，使每个子集中含有n/2个元素，而且S1中所有元素的和与S2中所有元素的和的差最大。这个算法的时间复杂性是什么？&nbsp;&nbsp;<a href='http://www.cnitblog.com/intrl/archive/2009/04/11/56261.html'>阅读全文</a><img src ="http://www.cnitblog.com/intrl/aggbug/56261.html" width = "1" height = "1" /><br><br><div align=right><a style="text-decoration:none;" href="http://www.cnitblog.com/intrl/" target="_blank">intrl</a> 2009-04-11 18:42 <a href="http://www.cnitblog.com/intrl/archive/2009/04/11/56261.html#Feedback" target="_blank" style="text-decoration:none;">发表评论</a></div>]]></description></item><item><title>【算法】相等元素问题</title><link>http://www.cnitblog.com/intrl/archive/2009/04/11/56260.html</link><dc:creator>intrl</dc:creator><author>intrl</author><pubDate>Sat, 11 Apr 2009 10:36:00 GMT</pubDate><guid>http://www.cnitblog.com/intrl/archive/2009/04/11/56260.html</guid><wfw:comment>http://www.cnitblog.com/intrl/comments/56260.html</wfw:comment><comments>http://www.cnitblog.com/intrl/archive/2009/04/11/56260.html#Feedback</comments><slash:comments>0</slash:comments><wfw:commentRss>http://www.cnitblog.com/intrl/comments/commentRss/56260.html</wfw:commentRss><trackback:ping>http://www.cnitblog.com/intrl/services/trackbacks/56260.html</trackback:ping><description><![CDATA[&nbsp;&nbsp;&nbsp;&nbsp; 摘要: 1.问题描述 <br>考虑元素唯一性问题：给出一个整数集合，假定这些整数存储在数组A[1…n]中，确定它们中是否存在两个相等的元素。请设计出一个有效算法来解决这个问题，你的算法的时间复杂性是多少？&nbsp;&nbsp;<a href='http://www.cnitblog.com/intrl/archive/2009/04/11/56260.html'>阅读全文</a><img src ="http://www.cnitblog.com/intrl/aggbug/56260.html" width = "1" height = "1" /><br><br><div align=right><a style="text-decoration:none;" href="http://www.cnitblog.com/intrl/" target="_blank">intrl</a> 2009-04-11 18:36 <a href="http://www.cnitblog.com/intrl/archive/2009/04/11/56260.html#Feedback" target="_blank" style="text-decoration:none;">发表评论</a></div>]]></description></item></channel></rss>